4z^2-7z-5=0

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Solution for 4z^2-7z-5=0 equation: 



4z^2-7z-5=0

a = 4; b = -7; c = -5;
Δ = b2-4ac
Δ = -72-4·4·(-5)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{129}}{2*4}=\frac{7-\sqrt{129}}{8}
$


$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{129}}{2*4}=\frac{7+\sqrt{129}}{8}
$

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